-16x^2+2400x=11600

Solution for -16x^2+2400x=11600 equation:

-16x^2+2400x=11600

We move all terms to the left:

-16x^2+2400x-(11600)=0

a = -16; b = 2400; c = -11600;
Δ = b2-4ac
Δ = 24002-4·(-16)·(-11600)
Δ = 5017600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5017600}=2240$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2400)-2240}{2*-16}=\frac{-4640}{-32}
=+145
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2400)+2240}{2*-16}=\frac{-160}{-32}
=+5
$